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	<title>Comments on: How to find the volume of oxygen gas collected in water decomposed?</title>
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	<link>http://blog.hybridcargurus.com/chemistry/how-to-find-the-volume-of-oxygen-gas-collected-in-water-decomposed/</link>
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		<title>By: Kevin</title>
		<link>http://blog.hybridcargurus.com/chemistry/how-to-find-the-volume-of-oxygen-gas-collected-in-water-decomposed/comment-page-1/#comment-1705</link>
		<dc:creator>Kevin</dc:creator>
		<pubDate>Wed, 15 Apr 2009 21:42:35 +0000</pubDate>
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		<description>Let&#039;s first balance the equation...

2H2O -&gt; 2H2 + O2


Then let&#039;s convert 1g of H2O to moles of H2O...

1.00g H2O x (1 mole )
..........1........(18.01g ) 
= .05552471 moles H2O


Then let&#039;s use the ideal gas equation to find the answer

PV = nRT

P = 1.00 atm
V = ?
n = .05552471 moles H2O
R = .0821
T = 25 degrees Celsius (or 298 K)

V = nRT
........P

V = (.05552471)(.0821)(298)
.................1.00 atm

Volume (V) = 1.35845641 Liters 

Rounded to 3 sig figs: 1.36 Liters</description>
		<content:encoded><![CDATA[<p><p>&#76;&#101;&#116;&#8217;s first weigh &#116;&#104;&#101; equation&#8230;</p>
<p>2H2O -> 2H2 + O2</p>
<p>&#84;&#104;&#101;&#110; &#108;&#101;&#116;&#8217;s convert 1g &#111;&#102; H2O &#116;&#111; moles &#111;&#102; H2O&#8230;</p>
<p>1.00g H2O x (1 mole )<br />
&#8230;&#8230;&#8230;.1&#8230;&#8230;..(18.01g )<br />
= .05552471 moles H2O</p>
<p>&#84;&#104;&#101;&#110; &#108;&#101;&#116;&#8217;s &#117;&#115;&#101; &#116;&#104;&#101; ideal gas equation &#116;&#111; find &#116;&#104;&#101; pledge</p>
<p>PV = nRT</p>
<p>P = 1.00 atm<br />
V = ?<br />
n = .05552471 moles H2O<br />
R = .0821<br />
T = 25 degrees Celsius (&#111;&#114; 298 K)</p>
<p>V = nRT<br />
&#8230;&#8230;..P</p>
<p>V = (.05552471)(.0821)(298)<br />
&#8230;&#8230;&#8230;&#8230;&#8230;..1.00 atm</p>
<p>Number (V) = 1.35845641 Liters </p>
<p>Rounded &#116;&#111; 3 sig figs: 1.36 Liters</p>
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