How to find the volume of oxygen gas collected in water decomposed?
April 14, 2009 in Chemistry
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Smilely questioned:
When fill up is subjected to an gripping current, it decomposes to hydrogen and oxygen gas. If 1.00g of fill up is moldy at 1.00 atm and 25 top Celsius, what number of oxygen gas is collected?
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Let’s first weigh the equation…
2H2O -> 2H2 + O2
Then let’s convert 1g of H2O to moles of H2O…
1.00g H2O x (1 mole )
……….1……..(18.01g )
= .05552471 moles H2O
Then let’s use the ideal gas equation to find the pledge
PV = nRT
P = 1.00 atm
V = ?
n = .05552471 moles H2O
R = .0821
T = 25 degrees Celsius (or 298 K)
V = nRT
……..P
V = (.05552471)(.0821)(298)
……………..1.00 atm
Number (V) = 1.35845641 Liters
Rounded to 3 sig figs: 1.36 Liters